Determine whether a given year is a leap year

Determine whether a given year is a leap year.

def leap_year(y):
    if y % 400 == 0:
        return True
    if y % 100 == 0:
        return False
    if y % 4 == 0:
        return True
    else:
        return False

print(leap_year(1900))    # False
print(leap_year(2004))    # True

See also

https://www.w3resource.com/python-exercises/date-time-exercise/python-date-time-exercise-2.php